Bond energies (HT only)

Emmanuel Opoku

Teacher

Emmanuel Opoku

Energy in Chemical Bonds

Key idea:

  • Energy is taken in to break bonds (endothermic).

  • Energy is given out when new bonds form (exothermic).

The overall energy change shows whether a reaction is exothermic or endothermic.


Conservation of Energy

Energy cannot be created or destroyed, it is only transferred.

Process

Flow of Energy

Type of Change

Breaking bonds

Taken in

Endothermic

Making bonds

Given out

Exothermic

Worked Examples

Example 1 - Forming Water

Question:

Calculate the energy change for the reaction below.

Displayed formula:

Bond Energies:

Bond

Bond Energy (kJ/mol)

H–H

436

O=O

498

O–H

464

STEP 1: Calculate total energy needed to break bonds and total energy released when making bonds

To do this, you need to count all the bonds in the reactants (bonds broken) and all the bonds in the products (bonds made). This is where the displayed formula comes in handy.

Remember to take the coefficients (stoichiometry) into account – a table is useful here.


BONDS BROKEN

Bond

Bond Energy (kJ/mol)

No. of Bonds

Energy (kJ/mol)

H–H

436

2

(436 x 2) = 872

O=O

498

1

(498 x 1) = 498

Total Energy In

1370

BONDS MADE

Bond

Bond Energy (kJ/mol)

No. of Bonds

Energy (kJ/mol)

O–H

464

4

(464 x 4) = 1856

Total Energy Out

1856

STEP 2: Calculate the overall energy change (ΔH)

This is an example of an exothermic reaction where energy is released to surroundings (indicated by a negative overall energy change)

No answer provided.

Example 2 - Reaction of Hydrogen and Bromine

Question:

Calculate the overall energy change (ΔH) for the reaction between hydrogen and bromine:

Displayed formula:

Bond Energies:

Bond

Bond Energy (kJ/mol)

H–H

436

Br–Br

193

H-Br

366

STEP 1: Calculate total energy needed to break bonds and total energy released when making bonds

BONDS BROKEN

Bond

Bond Energy (kJ/mol)

No. of Bonds

Energy (kJ/mol)

H–H

436

1

(436 x 1) = 436

Br-Br

193

1

(193 x 1) = 193

Total Energy In

629

BONDS MADE

Bond

Bond Energy (kJ/mol)

No. of Bonds

Energy (kJ/mol)

H–Br

366

2

(366 x 2 ) = 732

Total Energy Out

732

STEP 2: Calculate the overall energy change (ΔH)

This is another example of an exothermic reaction where energy is released to surroundings (indicated by a negative overall energy change)

No answer provided.

Example 3 - Reaction of Ethene and Bromine

Question:

Calculate the overall energy change (ΔH) for the reaction below.

Displayed formula:

Bond Energies:

Bond

Bond Energy (kJ/mol)

C=C

614

Br–Br

193

C–C

347

C–Br

276

STEP 1: Calculate total energy needed to break bonds and total energy released when making bonds

BONDS BROKEN

Bond

Bond Energy (kJ/mol)

No. of Bonds

Energy (kJ/mol)

C=C

614

1

(614 x 1) = 614

Br–Br

193

1

(193 x 1) = 193

Total Energy In

 

 

807

BONDS MADE

Bond

Bond Energy (kJ/mol)

No. of Bonds

Energy (kJ/mol)

C=C

347

1

(347 x 1) = 347

Br–Br

276

2

(276 x 2) = 552

Total Energy Out

 

 

899

STEP 2: Calculate the overall energy change (ΔH)

This reaction is also exothermic reaction where energy is released to surroundings (indicated by a negative overall energy change)

No answer provided.

Example 4 - Combustion of Methane

Question:

Calculate ΔH for the combustion of methane:

Displayed formula:

Bond Energies Provided:

Bond

Bond Energy (kJ/mol)

C–H

413

O=O

498

C=O

805

O–H

464

STEP 1: Calculate total energy needed to break bonds and total energy released when making bonds

BONDS BROKEN

Bond

Bond Energy (kJ/mol)

No. of Bonds

Energy (kJ/mol)

C–H

413

4

(413 x 4) = 1652

O=O

498

2

(498 x 2) = 996

Total Energy In

 

 

2648

BONDS MADE

Bond

Bond Energy (kJ/mol)

No. of Bonds

Energy (kJ/mol)

C–O

805

2

(805 x 2) = 1610

O=H

464

4

(464 x 4) = 1856

Total Energy Out

 

 

3466

STEP 2: Calculate the overall energy change (ΔH)

This reaction is strongly exothermic, indicated by a large, negative value for the overall energy change (ΔH) - usually the case for combustion reactions

No answer provided.

Challenging Example

Finding an Unknown Bond Energy

Question:

Find the N–N bond energy in this reaction, given

Displayed formula:

Bond Energies:

Bond

Bond Energy (kJ/mol)

N–H

388

O=O

498

N=N

944

O–H

463

N-N

x

STEP 1: Calculate total energy needed to break bonds and total energy released when making bonds

BONDS BROKEN

Bond

Bond Energy (kJ/mol)

No. of Bonds

Energy (kJ/mol)

N–N

x

1

(1x) = x

N–H

388

4

(388 x 4) = 1552

O=O

498

 1

(498 x 1) = 498

Total Energy In

x + 2050

BONDS MADE

Bond

Bond Energy (kJ/mol)

No. of Bonds

Energy (kJ/mol)

N–N

944

1

(944 x 1) = 944

O–H

463

4

(563 x 4) = 1852

Total Energy Out

2796

STEP 2: Calculate missing bond by substituting overall energy change given in question and rearranging to find x (missing bond enthalpy)

N–N bond energy = 113 kJ/mol

No answer provided.

Interpreting overall energy change (ΔH)

Sign of overall energy change (ΔH)

Meaning

In terms of bonds

Reaction Type

Positive (+)

Energy taken in from surroundings overall

More energy needed to break bonds than is released forming bonds

Endothermic

Negative (–)

Energy given out to surroundings

More energy released forming bonds than is needed to break them

Exothermic

Key Takeaways

Concept

Explanation

Breaking bonds

Energy taken in → endothermic

Making bonds

Energy given out out → exothermic

Overall

= Bonds broken – Bonds made

Exothermic Reactions

ΔH is a negative value

Endothermic Reactions

ΔH is a positive value

No answer provided.

Check Your Understanding

Recall

a) What is meant by bond energy?

Answer

a) Bond energy = energy required to break 1 mole of a specified bond in gaseous molecules.

b) Why is breaking bonds endothermic?

Answer

b) Breaking bonds is endothermic because energy must be absorbed to overcome the attractive forces in the bond.

c) Write the formula for ΔH.

Answer

c) (bonds broken)(bonds made).

d) What does a positive ΔH value show?

Answer

d) Positive overall endothermic (more energy absorbed than released).

Apply

e) Calculate the overall energy change,, for:

Displayed (structural) formulas:

Bond energies supplied

Bond

Bond enthalpy /

S=O

523

O=O

495

Answer

Count Bonds broken and made and find totals of each

Bond

No.

Broken

S=O (in)

523

4

O=O

495

1

495

broken

2587

Made

S=O (in )

523

6

made

 3138

Exothermic overall.

Challenge

f) Propane () combusts completely in oxygen as follows:

Displayed formula:

Given that the overall energy change for this reaction is , calculate the bond enthalpy for a C=O bond in carbon dioxide.

Bond Enthalpies

Bond

Bond enthalpy /

C–H

413

C–C

348

O=O

495

O–H

463

C=O

? (to find)

Answer

Combustion of propane:

Count bonds and totals

Bond

No.

Bonds Broken

C–C

348

2

696

C–H

413

8

3304

O=O

495

5

2475

broken

6475

Bonds Made

C=O

x

6

6x

O–H

463

6

3704

made

6x + 3704

Solve with brokenmade

(to 3 s.f)

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