The Arrhenius Equation

Lajoy Tucker

Teacher

Lajoy Tucker

The Arrhenius Equation Explained

The Arrhenius equation describes how reaction rate is dependent on temperature. An increase in temperature leads to an increase in the rate constant , meaning that the rate of reaction increases. Roughly each rise in T doubles the rate constant Rate = .

The is given as:

Diagram showing the Gibbs free energy equation with labelled terms for enthalpy, entropy, temperature in kelvin, and the gas constant value.

The Arrhenius constant accounts for the frequency of collisions and the orientation of molecules during a reaction and has the same units as the rate constant .

Temperature has an exponential influence on reaction rate because it appears in the denominator of the exponent in the equation.

Graph showing the rate constant increasing exponentially as temperature increases in kelvin.

Arrhenius Equation Explainer Video

Worked example:

Find the value of .

Given:

Answer

Logarithmic form of the equation

By taking the natural logarithm of both sides of the equation, the equation becomes:

This equation takes the form of a straight line,  .

where:

is plotted against

Gradient is

The y-intercept is .

The activation energy, , in and A can be calculated by plotting a graph of vs .

Diagram showing rearrangement of the Arrhenius equation into linear form to compare with the equation of a straight line for plotting ln(k) against 1/T.

Graph of ln(k) against 1/T showing a straight-line relationship with a negative gradient and y-intercept equal to ln(A).

So,

Key tips:

  • Activation energies are positive therefore the gradient must be negative

  • Values on the axes do not have to start at 0. Choose an appropriate scale based on the values given.

  • As rate is proportional to the rate constant k, sometimes ln(rate) is plotted on the y axis. All following calculation steps are the same.

No answer provided.

Worked Example

Given below is initial rate data collected at five different temperatures.

Complete the table calculating and ln(rate).

Plot a graph a use it to calculate the activation energy using ln(rate) .

Answer

 

 

 

 

  • Plot against

  • Draw a line of best fit

  • Calculate the gradient

  • Activation energy in

Arrhenius graph of ln(k) against 1/T showing a straight-line gradient used to calculate an activation energy of 46.2 kJ mol⁻¹.

Reminders:

  • Always convert temperature from Celsius to Kelvin 

  • Activation energy in the Arrhenius equation is in . If asked in , the divide by 1000

No answer provided.