Integration using Partial Fractions
Neil Trivedi
Teacher
Integration Using Partial Fractions
In this note, we will be integrating functions that involve expressing them in partial fractions first, and then applying integration by recognition. For more on how to express fractions in partial fractions, see our Partial Fractions note.
Example 1:
Evaluate.
Note: We cannot simply the denominator since the denominator expands to , which doesn’t differentiate to the form of the numerator. It is important that we always check this.
Step 1: Write in partial fractions.
We rewrite the RHS to match the same form as the LHS by cross-multiplying.

Equating the numerators, we solve for and by substituting suitable values for that makes one of the brackets equal to .
So, we have
Therefore, we are evaluating
Step 2: Make guesses as to what may differentiate to give each term in our integral.
• For , we will guess . The is a multiplier so we can ignore it in our guess.
• For , we will guess . Like before, we can ignore the in our guess because that’s a multiplier.
Step 3: Differentiate our guesses using the chain rule.
• For , the angle is the argument (what we’re taking of). In this case, the angle is
, which differentiates to . Then, when we differentiate the function of , the angle is reciprocated.
When is differentiated, the angle is reciprocated
Differentiated angle
• For , the angle is , which differentiates to . Then, when we differentiate the function of , the angle is reciprocated.
When is differentiated, the angle is reciprocated
Differentiated angle
Step 4: Adjust the constants.
• Our guess differentiates to give , but we wanted . So, we multiply both sides by the constant we want over the constant we have, which will be .
• Our guess differentiates to give , but we wanted . So, we multiply both sides by the constant we want over the constant we have, which will be .
Example 2:
a) Express in partial fractions.
Here, we have a fraction that has a repeated factor in the denominator, namely , so we express the partial fractions as
Step 1: Write the RHS as a single fraction. We want the denominator to be . We don’t cross-multiply in this case. Instead, we multiply the numerator and denominator of by , by and by .
We get:
Step 2: Equate the numerators and solve for , , and by substituting suitable values for that make one of the brackets equal to .
We will run out of options on what to substitute to eliminate one of the unknowns, so we choose the next easiest option which is .
Substitute our values of and ,
Now rearrange for ,
So, we have
b) Hence, find
We are evaluating
To note, the term is a power function and can be rewritten as .
Step 1: Make guesses as to what may differentiate to give each term in our integral.
• For , we will guess . The is a multiplier so we can ignore it in our guess.
• For , we will guess . Similarly, is a multiplier so we can ignore it in our guess.
• For , we will guess . With power functions, the power goes up by . The is a multiplier so we can ignore it in our guess.
Step 2: Differentiate the guesses using the chain rule.
• For , the angle is the argument (what we’re taking of). In this case, the angle is
, which differentiates to . Then, when we differentiate the function of , the angle is reciprocated.
When is differentiated, the angle is reciprocated
Differentiated angle
• For , the angle is , which differentiates to . Then, when we differentiate the function of , the angle is reciprocated.
When is differentiated, the angle is reciprocated
Differentiated angle
• For , the angle is what’s inside the bracket, which is in this case. The angle differentiates to give . Then, for the power function, we bring down the power, knock off the power, then keep the angle the same.
Angle stays the same
Differentiated angleDifferentiated power function
Step 3: Adjust the constants.
• Our guess differentiates to give , but we wanted . So, we multiply both sides by the constant we want over the constant we have, which here will be .
• Our guess differentiates to give , but we wanted . So, we multiply both sides by the constant we want over the constant we have, which here will be .
• Our differentiates to give , but we wanted . So, we multiply both sides by the constant we want over the constant we have, which will be .
Therefore, we are left with a final answer of,
Then if you want to rewrite without negative powers (not necessary) we will have,
Challenging Question