Sketching Quadratics

Neil Trivedi

Teacher

Neil Trivedi

Sketching Quadratics

A quadratic is an algebraic expression in which the highest power of is Quadratic equations are typically written in the form

where and are constants and

In this note, we will explore sketching the graphs of quadratic equations.

The graph of a quadratic is called a parabola.

If the coefficient of is positive, the graph would be a U-shape.

If the coefficient of is negative, the graph would be a ∩-shape.

When first introduced to the topic of sketching quadratics, you may have used a table of values to help you, where you substitute some values of into the quadratic equation to obtain the corresponding coordinates, then plot the coordinates onto the graph, and then connect the points on the graph with a curve.

In the table, you’d notice the symmetry of values which is why it has that parabolic U-shape.

Here, we will explore another way to approach sketching quadratics, where we only need to consider three features.

Features to Consider when Sketching Quadratics

1) The roots

These occur when and we can find them using methods such as factorising the quadratic equation, completing the square, or using the quadratic formula.

2) The intercept

This is where the graph intersects the axis (when and is represented by in the equation.

3) The shape

We determine whether the quadratic graph would be like a U-shape or an ∩-shape by looking at whether the coefficient of is positive or negative.

Example 1:

Sketch

Step 1: Determine the roots of the quadratic, the intercept, and the shape of the curve.

The roots occur when so we set

This quadratic can be factorised, so we will use this method to find the roots. For more information on factorising quadratics, please read our Factorising Quadratics notes.

When we factorise the above equation, we get

Now, we set each bracket equal to and then solve each one for Starting with the first bracket,

Adding to both sides,

Next, we solve

Subtracting from both sides,

Therefore, the roots of the quadratic occur when and

Next, we determine the intercept. This occurs when which we substitute into the quadratic equation to find the coordinate.

Therefore, the intercept is Notice that the coordinate of the intercept is equal to the constant at the end of the quadratic, independent of (the value of Going forward, this is how we will find it rather than setting

Finally, to determine the shape of the curve, we look at the coefficient of In this case, the coefficient is which is positive, so the quadratic will have a U-shape.

Step 2: Use the information determined in step 1 to sketch the graph of the quadratic.

Using the three pieces of information from above, we would get the following sketch:

No answer provided.

Example 2:

Sketch

Step 1: Determine the roots of the quadratic, the intercept, and the shape of the curve.

The roots occur when so we set

Firstly, we can move all the terms from the left-hand side to the right-hand side so that the is positive.

So,

This quadratic can be factorised using the difference of two squares principle and in doing so, we get

Now, we set each bracket equal to and then solve each one for Starting with the first bracket,

Subtracting from both sides,

Next, we solve

Adding to both sides,

Therefore, the roots of the quadratic occur when and

Alternatively, we could have solved this by rearranging the equation Firstly, we’d move the to the right-hand side so it goes from negative to positive.

Then, we square root both sides to get

Next, we determine the intercept. This is represented by the value of in the quadratic. Remember that we refer the equation is and not any rearranged one as the signs would have changed. In this case, so the intercept is

Finally, to determine the shape of the curve, we look at the coefficient of In this case, the coefficient is which is negative, so the quadratic will have an ∩-shape.

Step 2: Use the information determined in step 1 to sketch the graph of the quadratic.

Using the three pieces of information from above, we would get the following sketch:

No answer provided.

Example 3:

Sketch

Step 1: Determine the roots of the quadratic, the intercept, and the shape of the curve.

The roots occur when so we set

We can factorise this quadratic using the OI-OI method, coined by NeilDoesMaths. For more information on this method, please read our Factorising Quadratics note. Factorising the quadratic, we get

Now, we set each bracket equal to and then solve each one for Starting with the first bracket,

Adding to both sides,

Dividing both sides by

Next, we solve

Adding 1 to both sides,

Therefore, the roots of the quadratic occur when and

Next, we determine the intercept. This is represented by the value of in the quadratic. In this case, so the intercept is

Finally, to determine the shape of the curve, we look at the coefficient of In this case, the coefficient is which is positive, so the quadratic will have a U-shape.

Step 2: Use the information determined in step 1 to sketch the graph of the quadratic.

Using the three pieces of information from above, we would get the following sketch:

No answer provided.

Sometimes, we get quadratics that we cannot factorise easily, as the roots are surds, or find the roots of because the graph does not cross the axis.

In these cases, we can use the completing the square method. This allows us to find the roots that cannot easily be found by factorising, as well as identify the turning point of the graph and determine whether the quadratic has any real roots.

The turning point of a quadratic is the minimum or maximum point of the graph. When sketching quadratics, the turning point becomes another important feature to consider alongside the roots, the intercept, and the shape of the graph.

Here is a general quadratic graph with the turning point included.

For example, consider the quadratic We write this quadratic in completed square form. For more information on the process, please read our Completing the Square study note.

The quadratic in completed square form will be

The coordinate of the turning point is found by taking the value that’s inside the brackets and flipping the sign. Here, we have inside the brackets. We just flip the sign, and we would get the coordinate to be

The coordinate of the turning point is just the constant term outside the brackets. In this case, the constant term is so the coordinate is

Therefore, the coordinates of the turning point are

Notice that we have effectively transformed the graph to create the quadratic

Firstly, the inside the brackets translates the graph unit to the left, then the translates the graph units downwards.

The turning point of the graph of is After applying the transformations of left and down, the turning point moves to

For more information on transformations, please read our Transformation of Functions study note.

Transformations to Sketch Quadratics

We can sketch quadratics by considering transformations of the graph of

When transforming quadratic graphs, it is important to remember the following rules:

Changes inside the brackets affect the values and work in the opposite direction.

Changes outside the brackets affect the values and work in the same direction.

For example,

1) translates the graph units to the right. This increases all values by while the values remain the same.

2) translates the graph units downwards. This decreases all values by while the values remain the same.

Example 4:

Sketch the graphs of the following, indicating the turning point and any points of intersection with the coordinate axes:

a)

Step 1: Write down the transformation that changes the graph of to the graph of

Here, we have inside the brackets and outside. So, both the and values are affected. The graph shifts units to the right and units upwards. This is a translation by the vector

Step 2: Sketch the graph of by applying the transformations from step 1 to the graph of

Firstly, here is the graph of

The turning point of this graph is

Due to the translation, the turning point moves from to The shape and orientation of the graph do not change, only its position.

To find the intercept, we substitute into the equation.

Therefore, the intercept is

Once we translate the graph by the vector we get the following sketch.


b)

Step 1: Write down the transformation that changes the graph of to the graph of

For clarification, we can rewrite the quadratic as

Here, we have inside the brackets and outside. So, both the and values are affected.

For the graph shifts units to the left. This is a translation by the vector and all values decrease by

For we are multiplying all values by so this is a reflection in the axis.

Step 2: Sketch the graph of by applying the transformations from step 1 to the graph of

Firstly, here’s the graph of

The turning point of this quadratic is

To go from to we translate the graph units to the left. Hence, the turning point shifts from to

To find the intercept, we substitute into the equation.

Therefore, the intercept is

Finally, to go from to we reflect the graph in the axis. The coordinate of the turning point doesn’t change because it’s right on the mirror line (the axis).

However, for the intercept, we multiply its coordinate by to give us a new intercept of Also, the orientation of the graph flips, changing from a U-shape to an ∩-shape.

Therefore, once we applied the transformations, we get the following sketch:

No answer provided.

Example 5:

Sketch the graph of indicating the intersections with the coordinate axes and the turning point.

Step 1: Determine the roots of the quadratic (if any), the intercept, the shape of the curve, and the turning point.

Firstly, we can identify, from the quadratic equation, that the intercept of the graph is

We can also identify that the shape of the quadratic will be like a U-shape because the coefficient of which is is positive.

Now, to find the roots and the turning point, we must complete the square. For more practice on this, please read our Completing the Square notes. After completing the square, we’d get

The quadratic is now in completed square form. To find the roots, we make and then solve for

We have

Adding to both sides,

Dividing both sides by

Square rooting both sides,

Adding 3 to both sides,

Typing in the calculator, we get

Therefore, the roots of the quadratic are or

It is important to type these values in the calculator to know if they are positive or negative for our sketch. Alternatively, we can deduce this by recognising that so both roots must be positive.

Finally, we identify the turning point.

The coordinate of the turning point is the opposite of the value inside the brackets, which gives

The coordinate is the constant term outside the brackets, which is The that’s outside of the brackets does not affect the turning point.

Therefore, the coordinates of the turning point are

Step 2: Use the information obtained in step 1 to sketch the quadratic.

Using the information gathered:

The quadratic has a U-shape.

The intercept is

The roots of the quadratic are and

The turning point is

We can sketch the following quadratic graph:

No answer provided.

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